-x^2-(1.8*(10^-5)x)+(4.8*10^-6)=0

Solution for -x^2-(1.8*(10^-5)x)+(4.8*10^-6)=0 equation:

-x^2-(1.8(10^-5)x)+(4.8*10^-6)=0

We add all the numbers together, and all the variables

-1x^2-(1.8(10^-5)x)-6+4.8E=0


We calculate terms in parentheses: -(1.8(10^-5)x), so:

1.8(10^-5)x

We multiply parentheses

10x^2-5x

Back to the equation:

-(10x^2-5x)


We add all the numbers together, and all the variables

-1x^2-(10x^2-5x)+7.0477527766=0

We get rid of parentheses

-1x^2-10x^2+5x+7.0477527766=0

We add all the numbers together, and all the variables

-11x^2+5x+7.0477527766=0

a = -11; b = 5; c = +7.0477527766;
Δ = b2-4ac
Δ = 52-4·(-11)·7.0477527766
Δ = 335.10112217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{335.10112217}}{2*-11}=\frac{-5-\sqrt{335.10112217}}{-22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{335.10112217}}{2*-11}=\frac{-5+\sqrt{335.10112217}}{-22}
$